x^2+4(x-2)=x(x+1)4

Solution for x^2+4(x-2)=x(x+1)4 equation:

x^2+4(x-2)=x(x+1)4

We move all terms to the left:

x^2+4(x-2)-(x(x+1)4)=0

We multiply parentheses

x^2+4x-(x(x+1)4)-8=0


We calculate terms in parentheses: -(x(x+1)4), so:

x(x+1)4

We multiply parentheses

4x^2+4x

Back to the equation:

-(4x^2+4x)


We get rid of parentheses

x^2-4x^2+4x-4x-8=0

We add all the numbers together, and all the variables

-3x^2-8=0

a = -3; b = 0; c = -8;
Δ = b2-4ac
Δ = 02-4·(-3)·(-8)
Δ = -96
Delta is less than zero, so there is no solution for the equation